Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 37 of 494
The direction of the built-in electric field (\(\vec{E}_0\)) created inside the depletion region of a \(\text{p-n}\) junction points from:
A
The n-region to the p-region
B
The p-region to the n-region
C
The cathode terminal to the external anode wire
D
The surface of the diode to its geometric center
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: The n-region to the p-region
Concept:

Electric field lines always originate on positive charges and terminate on negative charges. Because the n-side of the depletion region contains positive donor ions and the p-side contains negative acceptor ions, the internal built-in electric field points from n to p.

Formula:

$$\vec{E} = -\nabla V \quad \text{(directed from positive space charge to negative space charge)}$$

Solution:

  • Positive space charge layer = n-side of the junction.


  • Negative space charge layer = p-side of the junction.


  • Therefore, the internal electric field \(\vec{E}_0\) points from the n-region toward the p-region.


Why other options are incorrect:

  • Option B: Electric fields point away from positive charges (n-side) and toward negative charges (p-side), not p to n.
  • Option C: Terminal wire connections are outside the semiconductor space-charge region.
  • Option D: The field is oriented across the planar junction interface, not radially from the surface.

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