Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 65 of 494
Which of the following biasing terminal configurations correctly establishes a forward-biased state in a \( \text{P-N} \) junction diode?

Anode (P)Cathode (N)V_P = -2 VV_N = -8 V
A
Anode at \( -2\text{ V} \) and Cathode at \( -8\text{ V} \)
B
Anode at \( -6\text{ V} \) and Cathode at \( +2\text{ V} \)
C
Anode at \( 0\text{ V} \) and Cathode at \( +5\text{ V} \)
D
Anode at \( -10\text{ V} \) and Cathode at \( -3\text{ V} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Anode at \( -2\text{ V} \) and Cathode at \( -8\text{ V} \)
Concept:

A diode is forward biased whenever the electric potential applied to the Anode (P-side) is strictly higher (more positive) than the potential applied to the Cathode (N-side).

Formula:

$$V_{\text{Anode}} > V_{\text{Cathode}} \implies V_{\text{bias}} = V_A - V_K > 0$$

Solution:

  • For Option A: \( V_A = -2\text{ V} \) and \( V_K = -8\text{ V} \).


  • \( V_{\text{bias}} = (-2\text{ V}) - (-8\text{ V}) = +6\text{ V} > 0 \), which is forward biased.


Why other options are incorrect:

  • Option B: \( V_A - V_K = -6 - (+2) = -8\text{ V} < 0 \) (Reverse biased).


  • Option C: \( V_A - V_K = 0 - (+5) = -5\text{ V} < 0 \) (Reverse biased).


  • Option D: \( V_A - V_K = -10 - (-3) = -7\text{ V} < 0 \) (Reverse biased).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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