Concept:The input angular frequency \( \omega = 2\pi f \) determines the input frequency, which doubles at the output of a full-wave rectifier.
Formula:$$\omega = 2\pi f_{\text{in}} \implies f_{\text{in}} = \frac{\omega}{2\pi}$$
$$f_{\text{ripple}} = 2 f_{\text{in}}$$
Solution:- From the given equation, \( \omega = 120\pi\text{ rad/s} \).
- $$f_{\text{in}} = \frac{120\pi}{2\pi} = 60\text{ Hz}$$
- For full-wave rectification:
- $$f_{\text{ripple}} = 2 \times 60\text{ Hz} = 120\text{ Hz}$$
Why other options are incorrect:- Option A: \( 60\text{ Hz} \) is the input frequency (and the ripple frequency for a half-wave rectifier).
- Option C: Quadrupling the input frequency is incorrect for a standard single-phase full-wave rectifier.
- Option D: Frequency is not halved.
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