Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 75 of 494
The ripple factor (\( \gamma \)) of a rectifier circuit, which quantifies the effectiveness of AC-to-DC conversion, is mathematically defined as:
A
\( \gamma = \dfrac{V_{\text{dc}}}{V_{\text{rms}}} \)
B
\( \gamma = \dfrac{V_{\text{rms}}}{V_{\text{dc}}} \)
C
\( \gamma = \sqrt{\left(\dfrac{V_{\text{rms}}}{V_{\text{dc}}}\right)^2 - 1} \)
D
\( \gamma = \sqrt{1 - \left(\dfrac{V_{\text{dc}}}{V_{\text{rms}}}\right)^2} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( \gamma = \sqrt{\left(\dfrac{V_{\text{rms}}}{V_{\text{dc}}}\right)^2 - 1} \)
Concept:

Ripple factor is the ratio of the effective (RMS) value of the AC ripple components to the pure DC output voltage.

Formula:

$$\gamma = \frac{V_{\text{ac, rms}}}{V_{\text{dc}}} = \frac{\sqrt{V_{\text{rms}}^2 - V_{\text{dc}}^2}}{V_{\text{dc}}} = \sqrt{\left(\frac{V_{\text{rms}}}{V_{\text{dc}}}\right)^2 - 1}$$

Solution:

  • Because total RMS voltage consists of orthogonal AC and DC parts (\( V_{\text{rms}}^2 = V_{\text{dc}}^2 + V_{\text{ac, rms}}^2 \)):


  • $$V_{\text{ac, rms}} = \sqrt{V_{\text{rms}}^2 - V_{\text{dc}}^2}$$


  • Dividing by \( V_{\text{dc}} \) gives \( \gamma = \sqrt{(V_{\text{rms}}/V_{\text{dc}})^2 - 1} \).


Why other options are incorrect:

  • Option A: This is the DC form factor ratio.


  • Option B: \( V_{\text{rms}}/V_{\text{dc}} \) is the total form factor \( F \), not the ripple factor.


  • Option D: Inverts the terms inside the square root.

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