Concept:Efficiency increases when more of the total power is converted into useful DC rather than unwanted AC ripple harmonics.
Formula:$$\eta = \frac{1}{1 + \gamma^2}$$
Solution:- Because total output power is partitioned into DC power and AC ripple power, decreasing the ripple factor (\( \gamma \)) directly increases conversion efficiency (\( \eta \)).
- For example, full-wave rectifiers have a lower ripple factor (\( 0.48 \) vs \( 1.21 \)) and double the efficiency (\( 81.2\% \) vs \( 40.6\% \)) of half-wave rectifiers.
Why other options are incorrect:- Option B: A higher ripple factor indicates more wasted AC ripple power, which reduces efficiency.
- Option C: Efficiency and ripple factor are directly related through the waveform form factor.
- Option D: There is no linear conservation law dictating that \( \eta + \gamma = 1 \).
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