Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 115 of 494
If an AC source with a frequency of \( 60\text{ Hz} \) is connected to a half-wave rectifier, the fundamental ripple frequency in the rectified output is:
A
30 Hz
B
60 Hz
C
120 Hz
D
240 Hz
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 60 Hz
Concept:

A half-wave rectifier conducts during only one half-cycle, producing one output pulse for each full AC input cycle.

Formula:

$$f_{\text{ripple, half-wave}} = f_{\text{in}}$$

Solution:

  • Since one pulse appears per cycle:


  • \( f_{\text{ripple}} = f_{\text{in}} = 60\text{ Hz} \).


Why other options are incorrect:

  • Option A: 30 Hz would imply sub-harmonic generation.
  • Option C: 120 Hz is the ripple frequency for a full-wave rectifier driven by a 60 Hz input.
  • Option D: 240 Hz is four times the fundamental frequency.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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