Concept:A full-wave bridge rectifier uses four diodes arranged in a bridge. Diagonal pairs alternate conduction on opposite half-cycles to direct load current in a single direction.
Formula:$$\text{Positive Half-Cycle: } D_1, D_3 \text{ ON} \quad | \quad \text{Negative Half-Cycle: } D_2, D_4 \text{ ON}$$
Solution:- During the positive half-cycle, diodes \( D_1 \) and \( D_3 \) are forward-biased and conduct in series with the load.
- During the negative half-cycle, diodes \( D_2 \) and \( D_4 \) are forward-biased and conduct through the load in the same direction.
- This ensures continuous, unidirectional current across both half-cycles.
Why other options are incorrect:- Option A: Simultaneous conduction of all four diodes would short-circuit the AC secondary winding.
- Option C: A single conducting diode produces half-wave rectification, not bridge rectification.
- Option D: Three conducting diodes would short-circuit the AC source.
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