Concept:A full-wave bridge rectifier conducts current through diagonal pairs of diodes during each half-cycle.
Formula:$$\text{Conducting Diodes per Half-Cycle} = 2$$
Solution:- During the positive half-cycle, diodes \( D_1 \) and \( D_3 \) are forward-biased and conduct in series with the load.
- During the negative half-cycle, diodes \( D_2 \) and \( D_4 \) are forward-biased and conduct in series with the load.
- Therefore, exactly 2 diodes conduct simultaneously during any given half-cycle.
Why other options are incorrect:- Option A: Only 1 diode conducts in a half-wave rectifier.
- Option C: 3 conducting diodes would short-circuit the AC supply.
- Option D: 4 diodes conducting simultaneously would create a direct short circuit across the transformer secondary.
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