Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 167 of 494
A diode's forward voltage increases from \( 0.70\text{ V} \) to \( 0.75\text{ V} \), causing the forward current to increase from \( 10\text{ mA} \) to \( 30\text{ mA} \). What is the dynamic (AC) resistance \( r_d \) of the diode over this operating range?
A
5.0 Ω
B
2.5 Ω
C
10.0 Ω
D
25.0 Ω
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 2.5 Ω
Concept:

Dynamic (AC) resistance is defined as the ratio of a change in forward voltage to the resulting change in forward current.

Formula:

$$r_d = \frac{\Delta V_f}{\Delta I_f}$$

Solution:

  • Change in voltage: \( \Delta V_f = 0.75\text{ V} - 0.70\text{ V} = 0.05\text{ V} \).


  • Change in current: \( \Delta I_f = 30\text{ mA} - 10\text{ mA} = 20\text{ mA} = 0.020\text{ A} \).


  • Dynamic resistance: \( r_d = \frac{0.05\text{ V}}{0.020\text{ A}} = \frac{50\text{ mV}}{20\text{ mA}} = 2.5\ \Omega \).


Why other options are incorrect:

  • Option A: 5.0 Ω results from using \( \Delta I = 10\text{ mA} \) instead of 20 mA.
  • Option C: 10.0 Ω results from using \( \Delta I = 5\text{ mA} \).
  • Option D: 25.0 Ω is \( 0.75 / 0.030 \), which calculates static (DC) resistance instead of dynamic (AC) resistance.

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