Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 186 of 494
A \( 12.0\text{ V} \) DC battery is connected across a series combination of a forward-biased silicon diode (\( V_D = 0.70\text{ V} \)) and a \( 560\ \Omega \) resistor. What is the voltage drop across the resistor?
A
12.00 V
B
0.70 V
C
11.30 V
D
6.00 V
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 11.30 V
Concept:

Applying Kirchhoff's Voltage Law (KVL) around a closed series loop shows that the battery voltage equals the sum of the voltage drops across the conducting diode and the series resistor.

Formula:

$$V_{\text{supply}} = V_D + V_R \implies V_R = V_{\text{supply}} - V_D$$

Solution:

  • Given: \( V_{\text{supply}} = 12.0\text{ V} \) and \( V_D = 0.70\text{ V} \).


  • Voltage across the resistor: \( V_R = 12.00\text{ V} - 0.70\text{ V} = 11.30\text{ V} \).


Why other options are incorrect:

  • Option A: 12.00 V assumes an ideal diode with zero forward voltage drop.
  • Option B: 0.70 V is the voltage drop across the diode, not the resistor.
  • Option D: 6.00 V assumes an equal voltage split between the components.

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