Concept:The RMS value for a half-wave rectified waveform is \( V_{\text{rms}} = V_m / 2 \), and for a full-wave rectified waveform it is \( V_{\text{rms}} = V_m / \sqrt{2} \).
Formula:$$V_{\text{rms, half-wave}} = \frac{V_m}{2} = \frac{100\text{ V}}{2} = 50.0\text{ V}$$
$$V_{\text{rms, full-wave}} = \frac{V_m}{\sqrt{2}} = \frac{100\text{ V}}{1.414} \approx 70.7\text{ V}$$
Solution:- Half-wave RMS: \( V_{\text{rms}} = \frac{100}{2} = 50.0\text{ V} \).
- Full-wave RMS: \( V_{\text{rms}} = \frac{100}{\sqrt{2}} \approx 70.7\text{ V} \).
Why other options are incorrect:- Option A: 35.3 V is \( 50 / \sqrt{2} \).
- Option B: 100 V is the peak voltage, not the RMS value.
- Option D: 31.8 V and 63.7 V are the DC (average) output values, not the RMS values.
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