Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 211 of 494
If the temperature of a reverse-biased silicon diode increases by \( 30^\circ\text{C} \), by approximately what factor will its reverse saturation leakage current \( I_0 \) increase?
A
2 times
B
8 times
C
3 times
D
30 times
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 8 times
Concept:

The reverse saturation current \( I_0 \) of a PN junction diode approximately doubles for every \( 10^\circ\text{C} \) increase in temperature.

Formula:

$$I_0(T_2) = I_0(T_1) \times 2^{\frac{\Delta T}{10}}$$

Solution:

  • Given: \( \Delta T = 30^\circ\text{C} \).


  • Number of \( 10^\circ\text{C} \) intervals: \( n = \frac{30}{10} = 3 \).


  • Current scaling factor: \( 2^3 = 8 \).


  • Therefore, the reverse leakage current increases by approximately 8 times.


Why other options are incorrect:

  • Option A: 2 times corresponds to a \( 10^\circ\text{C} \) increase.
  • Option C: 3 times incorrectly assumes a linear rather than exponential increase.
  • Option D: 30 times incorrectly scales directly with the temperature change.

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