Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 220 of 494
What is the ratio of the Peak Inverse Voltage across a diode in a center-tapped full-wave rectifier to that across a diode in a bridge rectifier, assuming both use identical peak secondary voltages \( V_m \)?
A
1 : 1
B
1 : 2
C
4 : 1
D
2 : 1
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: 2 : 1
Concept:

In a center-tapped rectifier, the PIV is \( 2V_m \), whereas in a bridge rectifier, the PIV is \( V_m \).

Formula:

$$\frac{\text{PIV}_{\text{center-tapped}}}{\text{PIV}_{\text{bridge}}} = \frac{2 V_m}{V_m} = \frac{2}{1} = 2 : 1$$

Solution:

  • Center-tapped diode PIV requirement: \( 2V_m \).


  • Bridge rectifier diode PIV requirement: \( V_m \).


  • The ratio is \( 2V_m / V_m = 2 : 1 \).


Why other options are incorrect:

  • Option A: The PIV ratings are not equal (\( 2V_m \ne V_m \)).
  • Option B: 1 : 2 inverts the ratio.
  • Option C: 4 : 1 overestimates the ratio.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Previous Question All Electronics MCQs Next Question

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.

Enter Arena Sprint iOS App Android App