Concept:Because a full-wave rectifier uses complementary diodes to conduct during both the positive and negative half-cycles, current flows through the load continuously over the full \( 360^\circ \) period.
Formula:$$\theta_{\text{total}} = \theta_{\text{positive}} + \theta_{\text{negative}} = 180^\circ + 180^\circ = 360^\circ = 2\pi\text{ rad}$$
Solution:- During the positive half-cycle (\( 0^\circ \text{ to } 180^\circ \)), the first diode group conducts.
- During the negative half-cycle (\( 180^\circ \text{ to } 360^\circ \)), the second diode group conducts.
- Together, load current flows continuously across all \( 360^\circ \) of the AC period.
Why other options are incorrect:- Option B: A conduction angle of \( 180^\circ \) corresponds to a half-wave rectifier.
- Option C: A conduction angle of \( 90^\circ \) occurs in phase-controlled thyristor circuits.
- Option D: Zero conduction angle means no current flows.
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