Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 324 of 494
What is the primary function of a high-value 'bleeder resistor' connected in parallel with the filter capacitor in a high-voltage DC power supply?
A
To amplify output ripple to high levels
B
To safely discharge stored charge from the filter capacitor when AC mains power is turned off, preventing electrical shock hazards
C
To convert the rectifier from full-wave to half-wave
D
To eliminate the need for an earth ground connection
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: To safely discharge stored charge from the filter capacitor when AC mains power is turned off, preventing electrical shock hazards
Concept:

Filter capacitors in high-voltage supplies can retain lethal electrical charge long after power is disconnected. A bleeder resistor connected across the capacitor provides a discharge path to safely dissipate this stored energy when power is turned off.

Formula:

$$v_C(t) = V_{\text{initial}} \exp\left(-\frac{t}{R_{\text{bleeder}} C}\right) \longrightarrow 0\text{ V}$$

Solution:

  • When power is disconnected from an unloaded supply, high-voltage capacitors can hold dangerous charge for hours.


  • A bleeder resistor provides a continuous discharge path (\( \tau = R_{\text{bleeder}} C \)) that drains stored voltage within seconds of shutdown.


  • It also provides a small minimum load current that improves output voltage regulation.


Why other options are incorrect:

  • Option A: Bleeder resistors do not increase ripple.
  • Option C: A parallel resistor does not change the rectifier topology.
  • Option D: A bleeder resistor does not replace equipment safety ground requirements.

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