Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 333 of 494
How can the emission color of an LED be continuously tuned across the visible spectrum (from red through green to violet) during semiconductor manufacturing?
A
By increasing the thickness of the external plastic lens
B
By increasing the length of the anode metallic lead
C
By adjusting the mole fraction ratio \( x \) in ternary or quaternary compound semiconductor alloys (such as \( \text{In}_x \text{Ga}_{1-x} \text{N} \) or \( \text{Al}_x \text{Ga}_{1-x} \text{As} \)) to engineer the band gap \( E_g \)
D
By operating the LED in reverse breakdown
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Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: By adjusting the mole fraction ratio \( x \) in ternary or quaternary compound semiconductor alloys (such as \( \text{In}_x \text{Ga}_{1-x} \text{N} \) or \( \text{Al}_x \text{Ga}_{1-x} \text{As} \)) to engineer the band gap \( E_g \)
Concept:

Bandgap engineering uses compound semiconductor alloys where varying the composition fraction \( x \) alters the lattice parameters and energy bandgap \( E_g(x) \), tuning the emitted photon wavelength \( \lambda = h c / E_g \).

Formula:

$$E_g(x) = x \cdot E_{g,1} + (1 - x) \cdot E_{g,2} - b \cdot x (1 - x) \implies \lambda_{\text{peak}} = \frac{h c}{E_g(x)}$$

Solution:

  • By varying the Indium fraction \( x \) in \( \text{In}_x \text{Ga}_{1-x} \text{N} \), the bandgap can be tuned from \( 0.7\text{ eV} \) (pure InN) up to \( 3.4\text{ eV} \) (pure GaN).


  • This allows fabricating LEDs across the entire visible spectrum (red, amber, green, blue, and violet) using the same alloy family.


Why other options are incorrect:

  • Option A: Plastic lens thickness does not alter photon emission bandgap physics.
  • Option B: Terminal lead length has no effect on emission wavelength.
  • Option D: Reverse breakdown does not produce efficient electroluminescence.

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