Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 353 of 494
When a \( \text{P-N} \) junction is forward-biased, what is the directional relationship between the applied electric field (\( E_{\text{applied}} \)) and the built-in electric field (\( E_{\text{built-in}} \))?
A
They act in the same direction, strengthening the net junction electric field
B
They act in opposite directions, reducing the net junction electric field
C
They are mutually perpendicular, causing charge carriers to follow circular paths
D
The applied field has no vector interaction with the internal space-charge field
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Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: They act in opposite directions, reducing the net junction electric field
Concept:

The built-in electric field points from the positive donor ions (N-side) to the negative acceptor ions (P-side). Forward bias applies an external electric field in the opposite direction (P-side to N-side).

Formula:

$$\vec{E}_{\text{net}} = \vec{E}_{\text{built-in}} - \vec{E}_{\text{applied}}$$

Solution:

  • \( \vec{E}_{\text{built-in}} \) points from the N-region to the P-region.


  • Forward bias applies a positive potential to the P-region and a negative potential to the N-region, establishing \( \vec{E}_{\text{applied}} \) from P to N.


  • Because these vectors are in opposite directions, the net electric field decreases, narrowing the depletion layer and allowing forward current flow.


Why other options are incorrect:

  • Option A: Reinforcement of the internal field occurs during reverse bias, where both fields point from N to P.
  • Option C: Perpendicular fields occur in Hall effect setups involving external magnetic fields, not standard axial diode biasing.
  • Option D: Electric fields superpose vectorially; the applied field directly alters the space-charge potential.

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