Physics Electronics PMDC Conceptual Practice
PMDC Verified Question 355 of 494
The small reverse saturation current (\( I_0 \)) that flows through a reverse-biased \( \text{P-N} \) junction prior to breakdown is primarily caused by the drift of:
A
Majority electrons from the N-region crossing into the P-region
B
Majority holes from the P-region crossing into the N-region
C
Immobile donor and acceptor ions dislodging from the crystal lattice
D
Thermally generated minority carriers swept across the junction by the internal field
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Thermally generated minority carriers swept across the junction by the internal field
Concept:

Reverse saturation current (leakage current) is caused by the drift of minority charge carriers generated thermally within or near the depletion region.

Formula:

$$I_{\text{reverse}} \approx I_0 = e A \left( \frac{D_n n_p}{L_n} + \frac{D_p p_n}{L_p} \right)$$

Solution:

  • Thermal energy continuously creates electron-hole pairs throughout the semiconductor.


  • Minority electrons in the P-region and minority holes in the N-region that wander into the depletion layer are swept across by the electric field.


  • This creates a small, temperature-dependent reverse leakage current (typically on the order of \( \mu\text{A} \) for Ge and \( \text{nA} \) for Si).


Why other options are incorrect:

  • Options A & B: Majority carriers face a large potential barrier in reverse bias and cannot cross the junction.
  • Option C: Immobile ionic cores remain bound within the semiconductor lattice and do not conduct current.

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