Concept:The conduction angle is the portion of the input AC cycle (measured in degrees or radians) during which the rectifying element conducts current to the load.
Formula:$$\theta_{\text{conduction}} = \pi \text{ rad} = 180^\circ \quad (\text{Ideal half-wave rectifier})$$
Solution:- An ideal diode conducts during the positive half-cycle, spanning from \( \theta = 0^\circ \) to \( \theta = 180^\circ \).
- It is reverse-biased and non-conducting throughout the negative half-cycle from \( \theta = 180^\circ \) to \( \theta = 360^\circ \).
- Therefore, the total conduction angle per cycle is \( 180^\circ \) (or \( \pi \text{ radians} \)).
Why other options are incorrect:- Option B: \( 90^\circ \) corresponds to a quarter-cycle, which occurs in phase-controlled thyristor circuits rather than uncontrolled diode rectifiers.
- Option C: \( 270^\circ \) corresponds to three-quarters of a cycle.
- Option D: \( 360^\circ \) is the total conduction angle of a full-wave rectifier across its active diode pairs.
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