Official Correct Choice:
Option D: The bridge rectifier requires diodes with a \( \text{PIV} \) rating of \( V_m \) and eliminates the need for a center-tapped transformer, while the center-tapped design requires a \( \text{PIV} \) of \( 2V_m \)
Concept:Bridge rectifiers require a lower Peak Inverse Voltage rating (\( \text{PIV} = V_m \)) and use standard two-wire transformers, whereas center-tapped designs require specialized transformers and diodes rated for \( \text{PIV} = 2V_m \).
Formula:$$\text{PIV}_{\text{Bridge}} = V_m \quad \text{vs} \quad \text{PIV}_{\text{Center-Tapped}} = 2V_m$$
Solution:- Both circuit topologies provide full-wave rectification with identical maximum efficiency (\( 81.2\% \)) and ripple frequency (\( 2f \)).
- In a bridge rectifier, each non-conducting diode is subjected to a maximum reverse voltage of \( V_m \), and a standard transformer can be used.
- In a center-tapped rectifier, each diode must withstand \( 2V_m \) across the full secondary winding, and a center-tapped transformer is required.
Why other options are incorrect:- Option A: Both rectifiers produce an identical ripple frequency of \( 2f \).
- Option B: The center-tapped rectifier requires twice the \( \text{PIV} \) rating (\( 2V_m \)) of the bridge rectifier (\( V_m \)).
- Option C: Both full-wave configurations share the same theoretical maximum efficiency of \( 81.2\% \).
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