Physics Electrostatics MDCAT 2010
PMDC Verified Question 129 of 131
Q.80 The magnitude of an electric field between two separated plates can be calculated by the relation
A
\( \Delta V = Ed \)
B
\( \Delta V = E/d \)
C
\( \Delta V = q_o d \)
D
\( E = \Delta V \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( \Delta V = Ed \)
1. Concept:

In a uniform electric field, such as between two parallel plates, the relationship between electric field strength, potential difference, and distance is known as the potential gradient.

2. Formula:

$$ E = \frac{\Delta V}{d} $$

3. Solution:

  • Rearranging the potential gradient formula gives us \( \Delta V = E \times d \).


4. Why other options are incorrect:

Option B divides by distance instead of multiplying. Option C incorporates charge which is irrelevant to the direct field-potential relationship. Option D implies the field and potential difference are perfectly identical, ignoring the spatial distance \( d \).

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