Concept:The magnitude of the electric field intensity (\( E \)) in any region of space is directly proportional to the density (closeness) of the electric field lines per unit area.
Formula:The electrostatic force experienced by a charge \( q \) in an electric field is given by:$$F = qE$$
Solution:- In the given diagram, the electric field lines are closest together (densest) at point A, meaning the electric field intensity is greatest at point A (\( E_A > E_B > E_C \)).
- Since electrostatic force \( F = qE \) is directly proportional to electric field strength, the charged particle will experience the largest force at point A.
Why other options are incorrect:- At point "B" and point "C": The field lines spread further apart (lower line density), meaning the electric field strength and resulting force are weaker than at point A.
- Same at all point: The force would only be uniform if the field lines were parallel and equally spaced (such as between large parallel plates). Here, the field is non-uniform.
Quality & Fidelity Assurance:
Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.