Physics Electrostatics SZABMU 2022
PMDC Verified Question 72 of 131
Q.132 \( 1 \text{ eV} \) is equal to:
A
\( 1.602 \times 10^{-19} \text{ J} \)
B
\( 16.02 \times 10^{-19} \text{ J} \)
C
\( 1620 \text{ J} \)
D
\( 162.0 \times 10^{-19} \text{ J} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( 1.602 \times 10^{-19} \text{ J} \)
1. Concept:

An electron-volt is the amount of kinetic energy gained by a single electron accelerating from rest through an electric potential difference of exactly one volt.

2. Formula:

$$ E = q \Delta V $$

3. Solution:

  • The charge of a single electron is \( q = 1.602 \times 10^{-19} \text{ C} \).


  • Multiply by 1 Volt: \( 1 \text{ eV} = (1.602 \times 10^{-19} \text{ C}) \times (1 \text{ V}) \).


  • Since \( 1 \text{ C} \cdot 1 \text{ V} = 1 \text{ J} \), the result is \( 1.602 \times 10^{-19} \text{ J} \).


4. Why other options are incorrect:

The other options feature incorrectly shifted decimal places. The fundamental charge of an electron strictly dictates the \( 1.602 \) coefficient.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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