Physics Electrostatics DUHS 2022
PMDC Verified Question 79 of 131
Q.139 The electric field intensity between two uniformly, oppositely charged parallel plates is:
A
\( \frac{\sigma}{2\epsilon_o} \)
B
\( \frac{\epsilon_o}{\sigma} \)
C
\( \frac{2\sigma}{\epsilon_o} \)
D
\( \frac{\sigma}{\epsilon_o} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( \frac{\sigma}{\epsilon_o} \)
1. Concept:

The total electric field between two opposite parallel plates is the additive sum of the uniform fields generated independently by each plate.

2. Formula:

$$ E = E_{positive} + E_{negative} $$

3. Solution:

  • A single infinite charged plate generates a field of \( E_1 = \frac{\sigma}{2\epsilon_0} \).


  • Between two oppositely charged plates, the field vectors point in the exact same direction, reinforcing each other.


  • Total Field: \( E = \frac{\sigma}{2\epsilon_0} + \frac{\sigma}{2\epsilon_0} = \frac{2\sigma}{2\epsilon_0} = \frac{\sigma}{\epsilon_o} \).


4. Why other options are incorrect:

Option A is the field strength for only a single sheet of charge, representing the region outside the plates or if one plate were removed. Options B and C are dimensionally inverted or incorrectly scaled.

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