1. Concept: For any circuit components strung in series, the identical total current must flow through them, guaranteeing that series capacitors hold the exact same magnitude of charge regardless of their individual capacities.
2. Formula: $$ C_{eq} = \frac{C_1 C_2}{C_1 + C_2} \quad \text{and} \quad Q = C_{eq} V_{total} $$
3. Solution: - Find equivalent capacitance: \( C_{eq} = \frac{6 imes 12}{6 + 12} = \frac{72}{18} = 4 \mu\text{F} \).
- Calculate the total charge pulled from the supply: \( Q_{total} = (4 \times 10^{-6} \text{ F}) \times 200 \text{ V} \).
- Result: \( Q_{total} = 800 imes 10^{-6} \text{ C} \).
- Adjusting the decimal for scientific notation yields \( 8 \times 10^{-4} \text{ C} \).
- Since they are in series, BOTH capacitors possess this identical exact charge.
4. Why other options are incorrect: Options B and C falsely assume capacitors in series possess different charges. Option D makes a catastrophic error regarding the 'micro' prefix, scaling the answer by a million.
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