Concept:Poiseuille's Law describes the pressure difference required to drive a viscous fluid through a narrow cylindrical pipe.
Formula:$$ Q = \frac{\pi \Delta P r^4}{8 \eta L} \implies \Delta P \propto \frac{1}{r^4} $$
Solution:- Since volume flow rate (\( Q \)), length (\( L \)), and viscosity (\( \eta \)) are constant, pressure \( P \) is inversely proportional to \( r^4 \).
- The ratio of diameters is \( 0.60 / 0.30 = 2 \). Thus, the ratio of radii is also 2.
- Comparing pressures: \( \frac{P_1}{P_2} = \left(\frac{r_2}{r_1}\right)^4 = (2)^4 = 16 \).
- The smaller needle requires 16 times more pressure.
Why other options are incorrect:Option A assumes a linear relation. Option B assumes an area relation (\( r^2 \)). Poiseuille's flow strictly scales with the fourth power of the radius.
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