Physics Force & Motion MDCAT 2009
PMDC Verified Question 133 of 137
A body is moving with an initial velocity of \( 2 \text{ kms}^{-1} \). After a time of 50 secs its velocity becomes \( 1.5 \text{ kms}^{-1} \). Its acceleration will be:
A
\( 30 \text{ m s}^{-2} \)
B
\( 20 \text{ m s}^{-2} \)
C
\( 40 \text{ m s}^{-2} \)
D
\( 10 \text{ m s}^{-2} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( 10 \text{ m s}^{-2} \)
Concept:

Calculate the rate of change of velocity using proper SI units.

Formula:

$$ a = \frac{v_f - v_i}{t} $$

Solution:

  • \( v_i = 2000 \text{ m/s} \), \( v_f = 1500 \text{ m/s} \), \( t = 50 \text{ s} \).


  • $$ a = \frac{1500 - 2000}{50} = -10 \text{ m/s}^2 $$


  • The magnitude is \( 10 \text{ m/s}^2 \).


Why other options are incorrect:

Failure to convert km to meters leads to wrong values.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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