Concept:The total velocity of a projectile is the vector sum of its horizontal and vertical components. As it rises against gravity, its kinetic energy decreases and converts to potential energy.
Solution:- At the point of projection, the projectile possesses its full initial vertical velocity (\( v_{iy} \)) and horizontal velocity (\( v_x \)).
- As it moves upward, \( v_x \) remains constant, but \( v_y \) strictly decreases, meaning the overall magnitude \( v = \sqrt{v_x^2 + v_y^2} \) decreases.
- The velocity is at its absolute minimum at the highest point (where \( v_y = 0 \)). It returns to its maximum magnitude right as it hits the ground (landing point). Assuming a ground-to-ground launch, projection and landing share the maximum speed.
Why other options are incorrect:The highest point has the
minimum velocity. Velocity is not constant across all points.
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