Physics Force & Motion SZABMU 2024
PMDC Verified Question 5 of 137
At what angle made by projectile with x-axis, we can get 1/4th value of maximum height achieved by
A
\( 30^\circ \)
B
\( 45^\circ \)
C
\( 60^\circ \)
D
\( 90^\circ \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( 30^\circ \)
Concept:

Relate height at a given angle to absolute maximum height (which occurs at 90 degrees).

Formula:

$$ H = H_{\text{max}} \sin^2\theta $$

Solution:

  • Maximum height is achieved when \( \theta = 90^\circ \) (\( \sin 90^\circ = 1 \)), so \( H_{\text{max}} = \frac{v_i^2}{2g} \).


  • We want \( H = \frac{1}{4}H_{\text{max}} \).


  • $$ \sin^2\theta = \frac{1}{4} $$


  • Taking the square root: \( \sin\theta = \frac{1}{2} \).


  • The angle whose sine is 0.5 is exactly \( 30^\circ \).


Why other options are incorrect:

At 45 degrees, \( H = 0.5 H_{\text{max}} \). At 60 degrees, \( H = 0.75 H_{\text{max}} \).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Previous Question All Force & Motion MCQs Next Question

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.

Enter Arena Sprint iOS App Android App