Physics Nuclear Physics UHS 2024
PMDC Verified Question 7 of 98
If we have "\(N_o\)" number of any radioactive element then after a period of "n" half-lives the number of atoms left behind is
A
\( 2^n N_o \)
B
\( \left(\frac{1}{2}\right)^n N_o \)
C
\( (1/2 N_o)^n \)
D
\( (2 N_o)^n \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( \left(\frac{1}{2}\right)^n N_o \)


Concept:

This is the fundamental universal mathematical equation for exponential radioactive decay based on discrete half-life intervals.

Solution:

  • After 1 half-life, you have \( \frac{1}{2} \) of the initial amount.


  • After 2 half-lives, you have \( \frac{1}{2} \times \frac{1}{2} = \left(\frac{1}{2}\right)^2 \) of the initial amount.


  • Generalizing this pattern, after \(n\) half-lives, the remaining amount is strictly multiplied by the fraction \( \left(\frac{1}{2}\right)^n \).


  • Yielding the standard formula: $$ N = N_0 \left(\frac{1}{2}\right)^n $$


Why other options are incorrect:

Option A describes exponential growth (like bacterial replication), not decay. Options C and D apply the exponent incorrectly to the initial quantity (\(N_o\)) itself, which makes zero mathematical sense.

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