Physics Nuclear Physics BUMHS 2024
PMDC Verified Question 15 of 98
Let T is the half-life of certain radioactive element and \(N_0\) are the number of atoms present in the sample at \(t = 0\). After time 3T, what percent of atoms present at \(t = 0\) will have been decayed?
A
12.5%
B
50%
C
87.5%
D
100%
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: 87.5%


Concept:

You must distinguish carefully between the percentage of atoms remaining and the percentage of atoms that have decayed.

Formula:

$$ \text{Remaining} = N_0 \left(\frac{1}{2}\right)^n $$

$$ \text{Decayed} = 100\% - \text{Remaining} $$

Solution:

  • A time of \(3T\) means exactly \(n = 3\) half-lives have passed.


  • Calculate the remaining fraction: $$ \left(\frac{1}{2}\right)^3 = \frac{1}{8} $$


  • Convert \(1/8\) to a percentage: \( \frac{1}{8} = 12.5\% \) of the atoms remain.


  • The question asks what percent decayed: $$ 100\% - 12.5\% = 87.5\% $$


Why other options are incorrect:

12.5% is the amount remaining, not decayed (this is a very common trap). 50% is the amount decayed after 1 half-life. Radioactive substances never reach 100% mathematical decay in finite time.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

Want to solve full-length papers under timed exam conditions?

Practice with zero-scroll lockdown sprints, dynamic latency zone timers, live peer selection telemetry, and the automated Amber mistake recovery loop.