Physics Rotational & Circular Motion MDCAT 2017
PMDC Verified Question 83 of 95
Angular speed of minutes hand of mechanical watch is:
A
\( \frac{\pi}{30} \text{ rad min}^{-1} \)
B
\( \frac{\pi}{2} \text{ rad min}^{-1} \)
C
\( \pi \text{ rad min}^{-1} \)
D
None of these
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: \( \frac{\pi}{30} \text{ rad min}^{-1} \)
Concept:

Angular speed is defined as the total angular displacement divided by the total time taken. The minute hand of a clock completes one full revolution in 60 minutes.

Formula:

$$ \omega = \frac{2\pi}{T} $$

Solution:

  • One complete revolution is \( 2\pi \text{ radians} \).
  • The time taken for one revolution of a minute hand is \( 60 \text{ minutes} \).
  • Therefore, \( \omega = \frac{2\pi}{60} \text{ rad/min} \).
  • Simplifying the fraction gives \( \frac{\pi}{30} \text{ rad min}^{-1} \).


Why other options are incorrect:

  • Option B assumes the hand completes a revolution in 4 minutes.
  • Option C assumes the hand completes a revolution in 2 minutes.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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