PMDC Verified Question 78 of 95
A \( 10 \text{ N} \) force moves a body around a circular path of radius \( 50 \text{ cm} \). What is work done in completing one revolution?
A
\( 5 \text{ J} \)
B
\( 0 \)
C
\( 31.42 \text{ J} \)
D
\( 500 \text{ J} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 0 \)
Concept:

Work is calculated as the dot product of force and displacement. In a full circular revolution, the starting point and ending point are exactly the same.

Formula:

$$ W = \vec{F} \cdot \vec{d} = Fd \cos(\theta) $$

Solution:

  • Because the body completes exactly one full revolution, its net displacement \( \vec{d} \) is 0.
  • Therefore, \( W = F \times 0 = 0 \).
  • Alternative logic: The centripetal force holding it in a circle acts exactly perpendicular (\( 90^\circ \)) to the instantaneous velocity. Since \( \cos(90^\circ) = 0 \), the work done by a centripetal force is always zero.


Why other options are incorrect:

  • Option A, Option C, Option D assume you calculate work using the distance (circumference) instead of the vector displacement, which is a fundamental misunderstanding of physics work.

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