Concept:To turn safely, the friction between tires and the road must provide exactly the necessary centripetal force to alter the vehicle's direction. If it cannot, inertia takes over.
Formula:$$ F_{\text{required}} = \frac{mv^2}{r} $$
Solution:- The maximum grip the tire has is its 'limiting static friction' \( (\mu F_n) \).
- If the cyclist goes too fast or turns too sharply, the \( F_{\text{required}} \) exceeds this physical limit.
- Because limiting friction is less than the required centripetal force, the cyclist loses traction, breaks physical contact laws, and skids linearly forward off the circular track.
Why other options are incorrect:- Option B means turning is safe and easy.
- Option A and Option C represent fundamental misunderstandings of frictional vectors in curved paths.
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