Physics Rotational & Circular Motion SZABMU 2023
PMDC Verified Question 32 of 95
If a stone of mass \( 1 \text{ Kg} \) is whirled in a horizontal circle (radius = \( 1 \text{ m} \)) with velocity \( 1 \text{ m/s} \), then the period is:
A
\( 4\pi \)
B
\( 2\pi \)
C
\( \frac{\pi}{2} \)
D
\( \frac{2\pi}{2} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( 2\pi \)
Concept:

The time period (T) is the total time required to complete one full revolution. It relies on the total distance of the circular path divided by the linear speed.

Formula:

$$ v = \frac{2\pi r}{T} \implies T = \frac{2\pi r}{v} $$

Solution:

  • Given radius \( r = 1 \text{ m} \).
  • Given linear velocity \( v = 1 \text{ m/s} \).
  • Substitute the values into the rearranged formula: \( T = \frac{2\pi(1)}{1} \).
  • This simplifies exactly to \( 2\pi \text{ seconds} \). (The mass of 1 Kg is a distractor).


Why other options are incorrect:

  • Option A, Option C, Option D result from incorrect arithmetic or using the wrong formula (like confusing velocity with angular velocity).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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