Physics Vectors & Equilibrium PMDC Conceptual Practice
PMDC Verified Question 29 of 50
If the position vector \(\vec{r}\) of a point of application of force and the force vector \(\vec{F}\) are collinear (pointing in the same direction), what is the resulting torque?
A
Maximum
B
Minimum but non-zero
C
Zero
D
Negative
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: Zero
Concept:
Calculating torque when the force is parallel to the displacement vector.

Formula:
$$\vec{\tau} = \vec{r} \times \vec{F} \implies \tau = rF \sin\theta$$

Solution:
If the vectors point in the same direction, the angle \(\theta\) between them is \(0^\circ\).
$$\tau = rF \sin(0^\circ) = rF(0) = 0$$
Therefore, the torque is exactly zero.

Why other options are incorrect:
  • A is incorrect because the maximum torque occurs when the force is perpendicular to the position vector (\(\theta = 90^\circ\)).
  • B and D are incorrect because the sine of \(0^\circ\) is zero, making the torque zero.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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