Concept:Scaling a unit vector to construct a vector with a specific direction and magnitude.
Formula:$$\vec{x} = |\vec{B}| \hat{A} = |\vec{B}| \frac{\vec{A}}{|\vec{A}|}$$
Solution:First, calculate the scalar magnitude of both vectors:
$$|\vec{B}| = \sqrt{4^2 + 2^2 + (-2)^2} = \sqrt{16 + 4 + 4} = \sqrt{24}$$
$$|\vec{A}| = \sqrt{2^2 + 3^2 + (-1)^2} = \sqrt{4 + 9 + 1} = \sqrt{14}$$
Now substitute these values into our equation for \(\vec{x}\):
$$\vec{x} = \sqrt{24} \frac{2\hat{i} + 3\hat{j} - \hat{k}}{\sqrt{14}} = \sqrt{\frac{24}{14}}(2\hat{i} + 3\hat{j} - \hat{k})$$
Simplify the radical fraction:
$$\sqrt{\frac{24}{14}} = \sqrt{\frac{12}{7}} = \sqrt{\frac{12 \times 7}{7^2}} = \frac{\sqrt{84}}{7} = \frac{2\sqrt{21}}{7}$$
Therefore, the constructed vector is:
$$\vec{x} = \frac{2\sqrt{21}}{7}(2\hat{i} + 3\hat{j} - \hat{k})$$
Why other options are incorrect:- B, C, and D use incorrect magnitude ratios or incorrect vector components that do not point in the direction of \(\vec{A}\).
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