Physics Work & Energy MDCAT 2008
PMDC Verified Question 106 of 108
A force \( 2\hat{i} + \hat{j} \) has moved its point of application from (2,3) to (6,5). What is work done?
A
-10
B
-18
C
+10
D
+18
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: +10
Concept:

Work done by a constant force is the dot product of the force vector and the displacement vector.

Formula:

$$ W = \vec{F} \cdot \vec{d} $$

Solution:

  • First, calculate the displacement vector \( \vec{d} \) by subtracting the initial position from the final position.


  • \( \vec{d} = (6 - 2)\hat{i} + (5 - 3)\hat{j} = 4\hat{i} + 2\hat{j} \)


  • Now, take the dot product of \( \vec{F} \) and \( \vec{d} \).


  • \( W = (2\hat{i} + \hat{j}) \cdot (4\hat{i} + 2\hat{j}) \)


  • \( W = (2 \times 4) + (1 \times 2) = 8 + 2 = 10 \text{ J} \)


Why other options are incorrect:

Subtracting the coordinates incorrectly or failing to apply the dot product rule (e.g., multiplying mismatched components) leads to incorrect negative or larger values like -10, -18, or +18.

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