Physics Work & Energy ETEA 2015
PMDC Verified Question 99 of 108
A 6.0 kg block is released from rest 80m above the ground. When it has fallen 60m its kinetic energy is approximately:
A
4800 J
B
3500 J
C
1200 J
D
120 J
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 3500 J
Concept:

According to the Law of Conservation of Energy, the loss in gravitational potential energy equals the gain in kinetic energy for a freely falling body.

Formula:

$$ \text{Loss in P.E} = \text{Gain in K.E} = mg\Delta h $$

Solution:

  • Mass (\( m \)) = 6.0 kg


  • Distance fallen (\( \Delta h \)) = 60 m (Note: we use the distance it has fallen, not its height from the ground).


  • Using \( g \approx 9.8 \text{ m/s}^2 \):


  • \( K.E = 6.0 \times 9.8 \times 60 = 58.8 \times 60 = 3528 \text{ J} \)


  • This is approximately 3500 J.


Why other options are incorrect:

Using the remaining height of 20m instead of the fallen distance gives \( 6 \times 9.8 \times 20 \approx 1200 \text{ J} \) (Option C). Using the total height 80m gives \( \approx 4800 \text{ J} \) (Option A).

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