Physics Work & Energy UHS 2022
PMDC Verified Question 40 of 108
Ignoring details associated with friction, extra forces exerted by arm and leg muscles, and other factors, we can consider a pole vault as the conversion of an athlete's running kinetic energy to gravitational potential energy. If an athlete is to lift his body 5m during a vault, what speed must he have when he plants his pole?
A
5 \( \text{ms}^{-1} \)
B
10 \( \text{ms}^{-1} \)
C
15 \( \text{ms}^{-1} \)
D
20 \( \text{ms}^{-1} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: 10 \( \text{ms}^{-1} \)
Concept:

Using the Law of Conservation of Energy, the initial horizontal kinetic energy is entirely converted into vertical gravitational potential energy at the peak of the vault.

Formula:

$$ \frac{1}{2}mv^2 = mgh $$

Solution:

  • The mass \( m \) cancels out on both sides: \( \frac{1}{2}v^2 = gh \).


  • Rearrange for velocity: \( v = \sqrt{2gh} \).


  • Height (\( h \)) = 5 m. Assume standard gravity \( g = 10 \text{ m/s}^2 \).


  • \( v = \sqrt{2 \times 10 \times 5} = \sqrt{100} \).


  • \( v = 10 \text{ m/s} \).


Why other options are incorrect:

Failing to multiply by 2 gives \( \sqrt{50} \approx 7 \). Assuming \( v = gh \) directly gives 50. Only 10 is mathematically sound.

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