Physics Work & Energy SZABMU 2022
PMDC Verified Question 47 of 108
In inter-conversion of energy, the work done against the friction is:
A
\( f + h \)
B
\( f - h \)
C
\( fh \)
D
\( f/h \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( fh \)
Concept:

Work is fundamentally defined as the product of force and the displacement over which it acts.

Formula:

$$ W = F \times d $$

Solution:

  • Let the frictional force be \( f \).


  • Let the displacement (or height/distance fallen) be \( h \).


  • The magnitude of the work done to overcome this friction over that distance is the product of the two: \( W = f \times h = fh \).


Why other options are incorrect:

Adding, subtracting, or dividing force and distance violates dimensional analysis (you cannot add Newtons to meters, and N/m is a spring constant, not energy).

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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