Physics Work & Energy ETEA 2022
PMDC Verified Question 52 of 108
A cyclist comes to a skidding stop in 10m. During this process, the opposing force on the cycle due to the road is 200N. How much work does the road do on the cycle?
A
-1800J
B
-2000J
C
2000J
D
1900J
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: -2000J
Concept:

Work done by a force opposing the direction of motion (like friction) is always negative because it removes kinetic energy from the system.

Formula:

$$ W = Fd \cos \theta $$

Solution:

  • Force of friction (\( F \)) = 200 N


  • Displacement (\( d \)) = 10 m


  • Since the force opposes motion, the angle \( \theta \) is \( 180^{\circ} \).


  • \( W = 200 \times 10 \times \cos(180^{\circ}) \)


  • \( W = 2000 \times (-1) = -2000 \text{ J} \)


Why other options are incorrect:

Option C (+2000J) implies the road pushed the bicycle forward, increasing its speed. Options A and D are calculation errors.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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