Chemistry Aldehydes & Ketones SZABMU 2024
PMDC Verified Question 4 of 94
The correct reactivity order of the following compounds towards nucleophile is:
A
\( H-CO-H < H-CO-R < R-CO-R \)
B
\( H-CO-R < H-CO-H < R-CO-R \)
C
\( H-CO-H > H-CO-R > R-CO-R \)
D
\( H-CO-H > R-CO-R > H-CO-R \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option C: \( H-CO-H > H-CO-R > R-CO-R \)
Concept:

Reactivity of carbonyl compounds toward nucleophilic attack decreases as steric hindrance (bulkiness) and electron-donating inductive effects increase.

Solution:

  • Methanal (\( H-CO-H \)): Has two tiny hydrogen atoms. Minimum steric hindrance and no electron-donating alkyl groups. Most reactive.


  • Aldehydes (\( H-CO-R \)): Have one bulky, electron-donating alkyl group (R). The carbon is slightly less positive and slightly more blocked. Intermediate reactivity.


  • Ketones (\( R-CO-R \)): Have two bulky, electron-donating alkyl groups. The carbon is sterically crowded and electronically stabilized. Least reactive.


  • Therefore, the correct decreasing order of reactivity is: \( H-CO-H > H-CO-R > R-CO-R \).


Why other options are incorrect:

Options A and B incorrectly rank ketones as more reactive than aldehydes. Option D incorrectly ranks ketones as more reactive than substituted aldehydes.

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