Chemistry Carboxylic Acids ETEA 2024
PMDC Verified Question 12 of 94
Acetic acid can be prepared by the hydrolysis of
A
Ethanal
B
Methanoic acid
C
Ethanol
D
Methyl cyanide
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: Methyl cyanide
Concept:

Hydrolysis of a nitrile yields a carboxylic acid with the exact same number of carbon atoms.

Formula:

$$ \text{CH}_3\text{C}\equiv\text{N} + 2\text{H}_2\text{O} \xrightarrow{\text{H}^+} \text{CH}_3\text{COOH} + \text{NH}_4^+ $$

Solution:

  • Acetic acid (\( \text{CH}_3\text{COOH} \)) contains exactly 2 carbon atoms.


  • To prepare it via hydrolysis, we must start with a 2-carbon nitrile.


  • Methyl cyanide (\( \text{CH}_3\text{CN} \)), also known as ethanenitrile, contains 2 carbon atoms.


  • Hydrolyzing the \( -\text{CN} \) group converts it into the \( -\text{COOH} \) group of acetic acid.


Why other options are incorrect:

Ethanal and ethanol require oxidation, not hydrolysis, to become acetic acid. Methanoic acid is already an acid and has only 1 carbon.

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