Chemistry Chemical Bonding MDCAT 2016
PMDC Verified Question 93 of 102
Count the number of \( \sigma \) (sigma) bonds and \( \pi \) (pi) bonds in the molecule of Ethene \( \left( \text{H}_2\text{C}=\text{CH}_2 \right) \):
A
1 \( \pi \) and 5 \( \sigma \) bonds
B
3 \( \pi \) and 3 \( \sigma \) bonds
C
2 \( \pi \) and 4 \( \sigma \) bonds
D
6 \( \pi \) and 6 \( \sigma \) bonds
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: 1 \( \pi \) and 5 \( \sigma \) bonds
Concept:

Every single bond is a sigma (\( \sigma \)) bond, and every double bond consists of one \( \sigma \) bond and one pi (\( \pi \)) bond.

Formula:

$$ \text{Total Bonds} = 4 \times (\text{C-H}) + 1 \times (\text{C=C}) $$

Solution:

  • There are 4 Carbon-Hydrogen single bonds, contributing 4 \( \sigma \) bonds.


  • There is 1 Carbon-Carbon double bond. This contributes 1 \( \sigma \) bond and 1 \( \pi \) bond.


  • Total \( \sigma \) bonds = \( 4 + 1 = 5 \).


  • Total \( \pi \) bonds = 1.


Why other options are incorrect:

  • Option B, Option C, Option D: These incorrectly count the fundamental bond types, likely confusing the number of electrons (a double bond has 4 electrons) with the number of discrete bonds.

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