Chemistry Chemical Bonding ETEA 2016
PMDC Verified Question 94 of 102
What will be the shape of a molecule which contains two sigma bond pairs and one lone pair?
A
Linear
B
V shape
C
Tetragonal
D
Triangular
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: V shape
Concept:

The geometry of a molecule with 3 total electron domains (2 bond pairs, 1 lone pair) is derived from a trigonal planar arrangement.

Formula:

$$ \text{Type} = \text{AB}_2\text{E} \implies \text{Bent / V-shape} $$

Solution:

  • The central atom is \( \text{sp}^2 \) hybridized because it has 3 electron domains.


  • The lone pair exerts a strong repulsive force on the two sigma bond pairs, pushing them downward.


  • The resulting visible geometry (ignoring the invisible lone pair) is an angular, bent, or V-shape (e.g., \( \text{SO}_2 \), \( \text{SnCl}_2 \)).


Why other options are incorrect:

  • Option A: Requires 2 bond pairs and 0 lone pairs.
  • Option C: Not a standard simple VSEPR geometry term.
  • Option D: Requires 3 bond pairs and 0 lone pairs.

Quality & Fidelity Assurance: Every question on BeambePrep is rigorously curated against the official PMDC syllabus with zero filler, zero out-of-syllabus content, and zero typos. When an authentic past paper originally contained a historical mistake or ambiguity from the examining board (such as UHS or NUMS), BeambePrep faithfully reflects the original paper while detailing the nuance and scientific consensus in the autopsy above.

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