Chemistry Chemical Bonding ETEA 2022
PMDC Verified Question 46 of 102
The first ionization energy of Al is less than Mg. This is due to:
A
Electron in the \( 3\text{p}^1 \) of Al
B
Al is less metallic than Mg
C
Mg comes first than Al
D
Ionization energy from Mg to Al decreases
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Propolis Cognitive Error Autopsy

Official Correct Choice:
Option A: Electron in the \( 3\text{p}^1 \) of Al
Concept:

Ionization energy generally increases across a period, but anomalies occur when electrons are removed from highly stable, fully filled subshells.

Formula:

$$ \text{Mg: } [\text{Ne}] \ 3s^2 \quad vs \quad \text{Al: } [\text{Ne}] \ 3s^2 \ 3p^1 $$

Solution:

  • Magnesium has a completely filled \( 3s \) subshell, which offers extra stability and requires more energy to disrupt.


  • Aluminum's outermost electron resides alone in the \( 3p \) subshell.


  • This \( 3p \) electron is higher in energy and partially shielded from the nucleus by the full \( 3s \) orbital, making it easier to remove.


Why other options are incorrect:

  • Option B, Option C, Option D: These are either consequences or simple factual statements that do not explain the quantum mechanical reason for the anomaly.

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