Chemistry Chemical Bonding DUHS 2022
PMDC Verified Question 49 of 102
Ethene (\( \text{H}_2\text{C}=\text{CH}_2 \)) has hybridization of C-atom:
A
\( \text{dsp}^3 \)
B
\( \text{sp} \)
C
\( \text{sp}^3 \)
D
\( \text{sp}^2 \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option D: \( \text{sp}^2 \)
Concept:

The hybridization of an atom can be quickly determined by its steric number (the sum of sigma bonds and lone pairs attached to it).

Formula:

$$ \text{Steric Number} = 3 \sigma \text{ bonds} + 0 \text{ lone pairs} = 3 $$

Solution:

  • In ethene, each Carbon atom forms a double bond with the other Carbon and single bonds with two Hydrogen atoms.


  • A double bond consists of one sigma bond and one pi bond. Therefore, each Carbon has exactly 3 sigma bonding domains.


  • A steric number of 3 dictates the mixing of one s-orbital and two p-orbitals, resulting in \( \text{sp}^2 \) hybridization.


Why other options are incorrect:

  • Option B: Occurs when carbon has triple bonds or two double bonds (steric number 2).
  • Option C: Occurs when carbon has four single bonds (steric number 4).

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