Chemistry Electrochemistry MDCAT 2015
PMDC Verified Question 69 of 73
Study the following facts, which of the following is correct:

\( Zn \rightarrow Zn^{+2} + 2e^- \quad E^\circ = +0.76V \)
\( Cu \rightarrow Cu^{+2} + 2e^- \quad E^\circ = -0.34V \)
A
\( Cu + Zn^{+2} \rightarrow Cu^{+2} + Zn \)
B
\( Cu^{+2} + Zn \rightarrow Cu + Zn^{+2} \)
C
\( Cu^{+2} + Zn^{+2} \rightarrow Cu + Zn \)
D
\( Cu^{+2} + Zn^{+2} \rightarrow Cu + Zn^{-2} \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( Cu^{+2} + Zn \rightarrow Cu + Zn^{+2} \)
Concept:

A spontaneous redox reaction occurs when a metal with a higher oxidation potential displaces a metal with a lower oxidation potential from its solution.

Solution:

  • The given values are standard oxidation potentials (notice the reactions show the loss of electrons).


  • Zinc has a much higher oxidation potential (\( +0.76 \text{ V} \)) than Copper (\( -0.34 \text{ V} \)).


  • Therefore, solid Zinc will spontaneously oxidize into \( Zn^{+2} \), and aqueous \( Cu^{+2} \) will be forced to undergo reduction into solid Copper.


  • The spontaneous overall reaction is: \( Zn_{(s)} + Cu^{+2}_{(aq)} \rightarrow Zn^{+2}_{(aq)} + Cu_{(s)} \).


Why other options are incorrect:

Option A represents the reverse (non-spontaneous) reaction. Options C and D show fundamentally impossible redox stoichiometry where both species undergo reduction.
Note on Signs: Standard reduction potentials are \( E^\circ_{\text{red}}(\text{Zn}) = -0.76\text{ V} \) and \( E^\circ_{\text{red}}(\text{Cu}) = +0.34\text{ V} \). Because the half-reactions in the question prompt depict electron loss (oxidation), the values given are standard oxidation potentials (\( +0.76\text{ V} \) and \( -0.34\text{ V} \)).

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