Chemistry Electrochemistry MDCAT 2015
PMDC Verified Question 70 of 73
Keeping in mind the electrode potential, which one of the following reactions is feasible?
A
\( Zn^{+2} + Cu \rightarrow Cu^{+2} + Zn \)
B
\( Fe + CuSO_4 \rightarrow FeSO_4 + Cu \)
C
\( Zn + MgSO_4 \rightarrow ZnSO_4 + Mg \)
D
\( Cd + MgSO_4 \rightarrow CdSO_4 + Mg \)
Tap any option to test your recall and reveal the step-by-step Propolis autopsy.

Propolis Cognitive Error Autopsy

Official Correct Choice:
Option B: \( Fe + CuSO_4 \rightarrow FeSO_4 + Cu \)
Concept:

A metal can displace another metal from its aqueous salt solution only if it sits "higher" (has a more negative reduction potential) in the electrochemical series.

Solution:

  • Iron (Fe) has a standard reduction potential of \( -0.44 \text{ V} \), whereas Copper (Cu) has a potential of \( +0.34 \text{ V} \).


  • Because Fe is a stronger reducing agent than Cu, solid Iron will easily oxidize and displace Copper ions from the sulfate solution.


  • The reaction \( Fe + CuSO_4 \rightarrow FeSO_4 + Cu \) is highly spontaneous and feasible.


Why other options are incorrect:

In option A, Cu cannot displace Zn. In option C, Zn cannot displace Mg (Mg is highly reactive). In option D, Cd cannot displace Mg.

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